LeetCode in Kotlin
1346. Check If N and Its Double Exist
Easy
Given an array arr of integers, check if there exists two integers N and M such that N is the double of M ( i.e. N = 2 * M).
More formally check if there exists two indices i and j such that :
i != j0 <= i, j < arr.lengtharr[i] == 2 * arr[j]
Example 1:
Input: arr = [10,2,5,3]
Output: true
Explanation: N = 10 is the double of M = 5,that is, 10 = 2 * 5.
Example 2:
Input: arr = [7,1,14,11]
Output: true
Explanation: N = 14 is the double of M = 7,that is, 14 = 2 * 7.
Example 3:
Input: arr = [3,1,7,11]
Output: false
Explanation: In this case does not exist N and M, such that N = 2 * M.
Constraints:
2 <= arr.length <= 500-10^3 <= arr[i] <= 10^3
Solution
class Solution {
fun checkIfExist(arr: IntArray): Boolean {
for (i in arr.indices) {
for (j in arr.indices) {
if (i != j && (arr[i] * 2 == arr[j] || arr[i] == arr[j] * 2)) {
return true
}
}
}
return false
}
}