LeetCode in Kotlin
1296. Divide Array in Sets of K Consecutive Numbers
Medium
Given an array of integers nums and a positive integer k, check whether it is possible to divide this array into sets of k consecutive numbers.
Return true if it is possible. Otherwise, return false.
Example 1:
Input: nums = [1,2,3,3,4,4,5,6], k = 4
Output: true
Explanation: Array can be divided into [1,2,3,4] and [3,4,5,6].
Example 2:
Input: nums = [3,2,1,2,3,4,3,4,5,9,10,11], k = 3
Output: true
Explanation: Array can be divided into [1,2,3] , [2,3,4] , [3,4,5] and [9,10,11].
Example 3:
Input: nums = [1,2,3,4], k = 3
Output: false
Explanation: Each array should be divided in subarrays of size 3.
Constraints:
1 <= k <= nums.length <= 1051 <= nums[i] <= 109
Note: This question is the same as 846: https://leetcode.com/problems/hand-of-straights/
Solution
class Solution {
fun isPossibleDivide(nums: IntArray, k: Int): Boolean {
nums.sort()
val map = HashMap<Int, Int>()
for (num in nums) {
map[num] = map.getOrDefault(num, 0) + 1
}
for (num in nums) {
if (map[num] == 0) {
continue
}
for (v in num until num + k) {
if (!map.containsKey(v) || map[v] == 0) {
return false
} else {
map[v] = map[v]!! - 1
}
}
}
return true
}
}