LeetCode in Kotlin

1253. Reconstruct a 2-Row Binary Matrix

Medium

Given the following details of a matrix with n columns and 2 rows :

• The matrix is a binary matrix, which means each element in the matrix can be 0 or 1.
• The sum of elements of the 0-th(upper) row is given as upper.
• The sum of elements of the 1-st(lower) row is given as lower.
• The sum of elements in the i-th column(0-indexed) is colsum[i], where colsum is given as an integer array with length n.

Your task is to reconstruct the matrix with upper, lower and colsum.

Return it as a 2-D integer array.

If there are more than one valid solution, any of them will be accepted.

If no valid solution exists, return an empty 2-D array.

Example 1:

Input: upper = 2, lower = 1, colsum = [1,1,1]

Output: [[1,1,0],[0,0,1]]

Explanation: [[1,0,1],[0,1,0]], and [[0,1,1],[1,0,0]] are also correct answers.

Example 2:

Input: upper = 2, lower = 3, colsum = [2,2,1,1]

Output: []

Example 3:

Input: upper = 5, lower = 5, colsum = [2,1,2,0,1,0,1,2,0,1]

Output: [[1,1,1,0,1,0,0,1,0,0],[1,0,1,0,0,0,1,1,0,1]]

Constraints:

• 1 <= colsum.length <= 10^5
• 0 <= upper, lower <= colsum.length
• 0 <= colsum[i] <= 2

Solution

class Solution {
    fun reconstructMatrix(upper: Int, lower: Int, colsum: IntArray): List<MutableList<Int>> {
        val res: MutableList<MutableList<Int>> = ArrayList()
        val n = colsum.size
        val upperRow = IntArray(n)
        val lowerRow = IntArray(n)
        var currentUpperSum = 0
        var currentLowerSum = 0
        for (i in 0 until n) {
            if (colsum[i] >= 1) {
                upperRow[i] = 1
                lowerRow[i] = 1
                currentUpperSum++
                currentLowerSum++
            }
        }
        for (i in 0 until n) {
            if (colsum[i] == 1 && currentUpperSum > upper) {
                currentUpperSum--
                upperRow[i] = 0
            }
        }
        for (i in upperRow.indices) {
            if (colsum[i] == 1 && upperRow[i] == 1) {
                currentLowerSum--
                lowerRow[i] = 0
            }
        }
        if (currentUpperSum != upper || currentLowerSum != lower) {
            return res
        }
        res.add(ArrayList())
        res.add(ArrayList())
        for (i in 0 until n) {
            res[0].add(upperRow[i])
            res[1].add(lowerRow[i])
        }
        return res
    }
}

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