LeetCode in Kotlin

1237. Find Positive Integer Solution for a Given Equation

Medium

Given a callable function f(x, y) with a hidden formula and a value z, reverse engineer the formula and return all positive integer pairs x and y where f(x,y) == z. You may return the pairs in any order.

While the exact formula is hidden, the function is monotonically increasing, i.e.:

The function interface is defined like this:

interface CustomFunction { public: // Returns some positive integer f(x, y) for two positive integers x and y based on a formula. int f(int x, int y); };

We will judge your solution as follows:

Solution

/*
 * // This is the custom function interface.
 * // You should not implement it, or speculate about its implementation
 * class CustomFunction {
 *     // Returns f(x, y) for any given positive integers x and y.
 *     // Note that f(x, y) is increasing with respect to both x and y.
 *     // i.e. f(x, y) < f(x + 1, y), f(x, y) < f(x, y + 1)
 *     fun f(x:Int, y:Int):Int {}
 * };
 */
class Solution {
    // This is the custom function interface.
    // You should not implement it, or speculate about its implementation
    fun interface CustomFunction {
        // Returns f(x, y) for any given positive integers x and y.
        // Note that f(x, y) is increasing with respect to both x and y.
        // i.e. f(x, y) < f(x + 1, y), f(x, y) < f(x, y + 1)
        fun f(x: Int, y: Int): Int
    }

    fun findSolution(customfunction: CustomFunction, z: Int): List<List<Int>> {
        val result: MutableList<List<Int>> = ArrayList()
        var x = 1
        var y = 1000
        while (x < 1001 && y > 0) {
            val functionResult = customfunction.f(x, y)
            if (functionResult < z) {
                x++
            } else if (functionResult > z) {
                y--
            } else {
                result.add(listOf(x++, y--))
            }
        }
        return result
    }
}