Medium
Given a list of folders folder
, return the folders after removing all sub-folders in those folders. You may return the answer in any order.
If a folder[i]
is located within another folder[j]
, it is called a sub-folder of it.
The format of a path is one or more concatenated strings of the form: '/'
followed by one or more lowercase English letters.
"/leetcode"
and "/leetcode/problems"
are valid paths while an empty string and "/"
are not.Example 1:
Input: folder = [“/a”,”/a/b”,”/c/d”,”/c/d/e”,”/c/f”]
Output: [“/a”,”/c/d”,”/c/f”]
Explanation: Folders “/a/b” is a subfolder of “/a” and “/c/d/e” is inside of folder “/c/d” in our filesystem.
Example 2:
Input: folder = [“/a”,”/a/b/c”,”/a/b/d”]
Output: [“/a”]
Explanation: Folders “/a/b/c” and “/a/b/d” will be removed because they are subfolders of “/a”.
Example 3:
Input: folder = [“/a/b/c”,”/a/b/ca”,”/a/b/d”]
Output: [“/a/b/c”,”/a/b/ca”,”/a/b/d”]
Constraints:
1 <= folder.length <= 4 * 104
2 <= folder[i].length <= 100
folder[i]
contains only lowercase letters and '/'
.folder[i]
always starts with the character '/'
.class Solution {
fun removeSubfolders(folder: Array<String>): List<String> {
val paths: MutableSet<String> = HashSet()
paths.addAll(folder)
val res: MutableList<String> = ArrayList()
for (f in folder) {
var lastSlash = f.lastIndexOf("/")
var isSub = false
while (lastSlash > 0) {
val upperDir = f.substring(0, lastSlash)
if (paths.contains(upperDir)) {
isSub = true
break
}
lastSlash = upperDir.lastIndexOf("/")
}
if (!isSub) {
res.add(f)
}
}
return res
}
}