Hard
There are n
items each belonging to zero or one of m
groups where group[i]
is the group that the i
-th item belongs to and it’s equal to -1
if the i
-th item belongs to no group. The items and the groups are zero indexed. A group can have no item belonging to it.
Return a sorted list of the items such that:
beforeItems[i]
is a list containing all the items that should come before the i
-th item in the sorted array (to the left of the i
-th item).Return any solution if there is more than one solution and return an empty list if there is no solution.
Example 1:
Input: n = 8, m = 2, group = [-1,-1,1,0,0,1,0,-1], beforeItems = [[],[6],[5],[6],[3,6],[],[],[]]
Output: [6,3,4,1,5,2,0,7]
Example 2:
Input: n = 8, m = 2, group = [-1,-1,1,0,0,1,0,-1], beforeItems = [[],[6],[5],[6],[3],[],[4],[]]
Output: []
Explanation: This is the same as example 1 except that 4 needs to be before 6 in the sorted list.
Constraints:
1 <= m <= n <= 3 * 104
group.length == beforeItems.length == n
-1 <= group[i] <= m - 1
0 <= beforeItems[i].length <= n - 1
0 <= beforeItems[i][j] <= n - 1
i != beforeItems[i][j]
beforeItems[i]
does not contain duplicates elements.import java.util.LinkedList
import java.util.Queue
class Solution {
fun sortItems(n: Int, m: Int, group: IntArray, beforeItems: List<List<Int>>): IntArray {
var totalGroups = m
val indexGroupMap: MutableMap<Int, MutableList<Int>> = HashMap()
for (i in 0 until n) {
if (group[i] == -1) {
group[i] = totalGroups
indexGroupMap[totalGroups] = ArrayList()
indexGroupMap[totalGroups]!!.add(i)
totalGroups++
} else {
indexGroupMap.putIfAbsent(group[i], ArrayList())
indexGroupMap[group[i]]!!.add(i)
}
}
val externalInMap = IntArray(totalGroups)
val internalInMap = IntArray(n)
val externalGraph: MutableMap<Int, MutableList<Int>> = HashMap()
val internalGraph: MutableMap<Int, MutableList<Int>> = HashMap()
for (i in beforeItems.indices) {
if (beforeItems[i].isNotEmpty()) {
val groupNumber = group[i]
for (j in beforeItems[i].indices) {
val prevItem = beforeItems[i][j]
val prevGroupNumber = group[prevItem]
if (groupNumber == prevGroupNumber) {
internalGraph.putIfAbsent(prevItem, ArrayList())
internalGraph[prevItem]!!.add(i)
internalInMap[i]++
} else {
externalGraph.putIfAbsent(prevGroupNumber, ArrayList())
externalGraph[prevGroupNumber]!!.add(groupNumber)
externalInMap[groupNumber]++
}
}
}
}
val externalQueue: Queue<Int> = LinkedList()
for (i in 0 until totalGroups) {
if (externalInMap[i] == 0) {
externalQueue.offer(i)
}
}
val res = IntArray(n)
var resIndex = 0
while (externalQueue.isNotEmpty()) {
val curGroup = externalQueue.poll()
val internalQueue: Queue<Int> = LinkedList()
if (indexGroupMap.containsKey(curGroup)) {
for (item in indexGroupMap[curGroup]!!) {
if (internalInMap[item] == 0) {
internalQueue.offer(item)
}
}
}
while (internalQueue.isNotEmpty()) {
val curItem = internalQueue.poll()
res[resIndex] = curItem
resIndex++
if (internalGraph.containsKey(curItem)) {
for (nextItemInGroup in internalGraph[curItem]!!) {
internalInMap[nextItemInGroup]--
if (internalInMap[nextItemInGroup] == 0) {
internalQueue.offer(nextItemInGroup)
}
}
}
}
if (externalGraph.containsKey(curGroup)) {
for (nextGroup in externalGraph[curGroup]!!) {
externalInMap[nextGroup]--
if (externalInMap[nextGroup] == 0) {
externalQueue.offer(nextGroup)
}
}
}
}
return if (resIndex == n) res else intArrayOf()
}
}