LeetCode in Kotlin

1123. Lowest Common Ancestor of Deepest Leaves

Medium

Given the root of a binary tree, return the lowest common ancestor of its deepest leaves.

Recall that:

Example 1:

Input: root = [3,5,1,6,2,0,8,null,null,7,4]

Output: [2,7,4]

Explanation: We return the node with value 2, colored in yellow in the diagram. The nodes coloured in blue are the deepest leaf-nodes of the tree. Note that nodes 6, 0, and 8 are also leaf nodes, but the depth of them is 2, but the depth of nodes 7 and 4 is 3.

Example 2:

Input: root = [1]

Output: [1]

Explanation: The root is the deepest node in the tree, and it’s the lca of itself.

Example 3:

Input: root = [0,1,3,null,2]

Output: [2]

Explanation: The deepest leaf node in the tree is 2, the lca of one node is itself.

Constraints:

Note: This question is the same as 865: https://leetcode.com/problems/smallest-subtree-with-all-the-deepest-nodes/

Solution

import com_github_leetcode.TreeNode

/*
 * Example:
 * var ti = TreeNode(5)
 * var v = ti.`val`
 * Definition for a binary tree node.
 * class TreeNode(var `val`: Int) {
 *     var left: TreeNode? = null
 *     var right: TreeNode? = null
 * }
 */
class Solution {
    fun lcaDeepestLeaves(root: TreeNode?): TreeNode? {
        if (root == null) {
            return null
        }
        val leftDep = getDep(root.left)
        val rightDep = getDep(root.right)
        return if (leftDep == rightDep) {
            root
        } else {
            if (leftDep > rightDep) {
                lcaDeepestLeaves(root.left)
            } else {
                lcaDeepestLeaves(root.right)
            }
        }
    }

    fun getDep(root: TreeNode?): Int {
        return if (root == null) {
            0
        } else 1 + Math.max(getDep(root.left), getDep(root.right))
    }
}