LeetCode in Kotlin
1108. Defanging an IP Address
Easy
Given a valid (IPv4) IP address, return a defanged version of that IP address.
A defanged IP address replaces every period "." with "[.]".
Example 1:
Input: address = “1.1.1.1”
Output: “1[.]1[.]1[.]1”
Example 2:
Input: address = “255.100.50.0”
Output: “255[.]100[.]50[.]0”
Constraints:
- The given
addressis a valid IPv4 address.
Solution
class Solution {
fun defangIPaddr(address: String): String {
return address.replace(".", "[.]")
}
}