LeetCode in Kotlin

1041. Robot Bounded In Circle

Medium

On an infinite plane, a robot initially stands at (0, 0) and faces north. Note that:

The robot can receive one of three instructions:

The robot performs the instructions given in order, and repeats them forever.

Return true if and only if there exists a circle in the plane such that the robot never leaves the circle.

Example 1:

Input: instructions = “GGLLGG”

Output: true

Explanation: The robot is initially at (0, 0) facing the north direction.

“G”: move one step. Position: (0, 1). Direction: North.

“G”: move one step. Position: (0, 2). Direction: North.

“L”: turn 90 degrees anti-clockwise. Position: (0, 2). Direction: West.

“L”: turn 90 degrees anti-clockwise. Position: (0, 2). Direction: South.

“G”: move one step. Position: (0, 1). Direction: South.

“G”: move one step. Position: (0, 0). Direction: South.

Repeating the instructions, the robot goes into the cycle: (0, 0) –> (0, 1) –> (0, 2) –> (0, 1) –> (0, 0).

Based on that, we return true.

Example 2:

Input: instructions = “GG”

Output: false

Explanation: The robot is initially at (0, 0) facing the north direction.

“G”: move one step. Position: (0, 1). Direction: North.

“G”: move one step. Position: (0, 2). Direction: North.

Repeating the instructions, keeps advancing in the north direction and does not go into cycles.

Based on that, we return false.

Example 3:

Input: instructions = “GL”

Output: true

Explanation: The robot is initially at (0, 0) facing the north direction.

“G”: move one step. Position: (0, 1). Direction: North.

“L”: turn 90 degrees anti-clockwise. Position: (0, 1). Direction: West.

“G”: move one step. Position: (-1, 1). Direction: West.

“L”: turn 90 degrees anti-clockwise. Position: (-1, 1). Direction: South.

“G”: move one step. Position: (-1, 0). Direction: South.

“L”: turn 90 degrees anti-clockwise. Position: (-1, 0). Direction: East.

“G”: move one step. Position: (0, 0). Direction: East.

“L”: turn 90 degrees anti-clockwise. Position: (0, 0). Direction: North.

Repeating the instructions, the robot goes into the cycle: (0, 0) –> (0, 1) –> (-1, 1) –> (-1, 0) –> (0, 0).

Based on that, we return true.

Constraints:

Solution

class Solution {
    fun isRobotBounded(instructions: String): Boolean {
        val dir = arrayOf(intArrayOf(0, 1), intArrayOf(-1, 0), intArrayOf(0, -1), intArrayOf(1, 0))
        var i = 0
        var x = 0
        var y = 0
        for (s in instructions.indices) {
            if (instructions[s] == 'L') {
                i = (i + 1) % 4
            } else if (instructions[s] == 'R') {
                i = (i + 3) % 4
            } else {
                x += dir[i][0]
                y += dir[i][1]
            }
        }
        return x == 0 && y == 0 || i != 0
    }
}