LeetCode in Kotlin
1015. Smallest Integer Divisible by K
Medium
Given a positive integer k, you need to find the length of the smallest positive integer n such that n is divisible by k, and n only contains the digit 1.
Return the length of n. If there is no such n, return -1.
Note: n may not fit in a 64-bit signed integer.
Example 1:
Input: k = 1
Output: 1
Explanation: The smallest answer is n = 1, which has length 1.
Example 2:
Input: k = 2
Output: -1
Explanation: There is no such positive integer n divisible by 2.
Example 3:
Input: k = 3
Output: 3
Explanation: The smallest answer is n = 111, which has length 3.
Constraints:
1 <= k <= 105
Solution
class Solution {
fun smallestRepunitDivByK(k: Int): Int {
var n = 0
if (k % 2 == 0 || k % 5 == 0) {
return -1
}
var i = 1
while (i <= k) {
n = (n * 10 + 1) % k
if (n == 0) {
return i
}
i++
}
return -1
}
}