LeetCode in Kotlin

1003. Check If Word Is Valid After Substitutions

Medium

Given a string s, determine if it is valid.

A string s is valid if, starting with an empty string t = "", you can transform t into s after performing the following operation any number of times:

• Insert string "abc" into any position in t. More formally, t becomes tleft + "abc" + tright, where t == tleft + tright. Note that tleft and tright may be empty.

Return true if s is a valid string, otherwise, return false.

Example 1:

Input: s = “aabcbc”

Output: true

Explanation: “” -> “abc” -> “aabcbc” Thus, “aabcbc” is valid.

Example 2:

Input: s = “abcabcababcc”

Output: true

Explanation: “” -> “abc” -> “abcabc” -> “abcabcabc” -> “abcabcababcc” Thus, “abcabcababcc” is valid.

Example 3:

Input: s = “abccba”

Output: false

Explanation: It is impossible to get “abccba” using the operation.

Constraints:

• 1 <= s.length <= 2 * 104
• s consists of letters 'a', 'b', and 'c'

Solution

import java.util.Deque
import java.util.LinkedList

class Solution {
    fun isValid(s: String): Boolean {
        val stack: Deque<Char> = LinkedList()
        for (c in s.toCharArray()) {
            if (c == 'c') {
                if (stack.isEmpty() || stack.pop() != 'b') {
                    return false
                }
                if (stack.isEmpty() || stack.pop() != 'a') {
                    return false
                }
            } else {
                stack.push(c)
            }
        }
        return stack.isEmpty()
    }
}

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