Medium
A binary string is monotone increasing if it consists of some number of 0
’s (possibly none), followed by some number of 1
’s (also possibly none).
You are given a binary string s
. You can flip s[i]
changing it from 0
to 1
or from 1
to 0
.
Return the minimum number of flips to make s
monotone increasing.
Example 1:
Input: s = “00110”
Output: 1
Explanation: We flip the last digit to get 00111.
Example 2:
Input: s = “010110”
Output: 2
Explanation: We flip to get 011111, or alternatively 000111.
Example 3:
Input: s = “00011000”
Output: 2
Explanation: We flip to get 00000000.
Constraints:
1 <= s.length <= 105
s[i]
is either '0'
or '1'
.class Solution {
fun minFlipsMonoIncr(s: String): Int {
var ones = 0
var flips = 0
for (element in s) {
if (element == '1') {
ones++
} else {
flips = (flips + 1).coerceAtMost(ones)
}
}
return flips
}
}