Easy
International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows:
'a' maps to ".-",'b' maps to "-...",'c' maps to "-.-.", and so on.For convenience, the full table for the 26 letters of the English alphabet is given below:
[”.-“,”-…”,”-.-.”,”-..”,”.”,”..-.”,”–.”,”….”,”..”,”.—”,”-.-“,”.-..”,”–”,”-.”,”—”,”.–.”,”–.-“,”.-.”,”…”,”-“,”..-“,”…-“,”.–”,”-..-“,”-.–”,”–..”]
Given an array of strings words where each word can be written as a concatenation of the Morse code of each letter.
"cab" can be written as "-.-..--...", which is the concatenation of "-.-.", ".-", and "-...". We will call such a concatenation the transformation of a word.Return the number of different transformations among all words we have.
Example 1:
Input: words = [“gin”,”zen”,”gig”,”msg”]
Output: 2
Explanation: The transformation of each word is:
“gin” -> “–…-.”
“zen” -> “–…-.”
“gig” -> “–…–.”
“msg” -> “–…–.”
There are 2 different transformations: “–…-.” and “–…–.”.
Example 2:
Input: words = [“a”]
Output: 1
Constraints:
1 <= words.length <= 1001 <= words[i].length <= 12words[i] consists of lowercase English letters.class Solution {
    fun uniqueMorseRepresentations(words: Array<String>): Int {
        val morse = arrayOf(
            ".-", "-...", "-.-.", "-..", ".", "..-.", "--.", "....", "..", ".---", "-.-", ".-..",
            "--", "-.", "---", ".--.", "--.-", ".-.", "...", "-", "..-", "...-", ".--", "-..-",
            "-.--", "--..",
        )
        val set: MutableSet<String> = HashSet()
        for (word in words) {
            val temp = StringBuilder()
            for (c in word.toCharArray()) {
                temp.append(morse[c.code - 'a'.code])
            }
            set.add(temp.toString())
        }
        return set.size
    }
}