Medium
Given a directed acyclic graph (DAG) of n
nodes labeled from 0
to n - 1
, find all possible paths from node 0
to node n - 1
and return them in any order.
The graph is given as follows: graph[i]
is a list of all nodes you can visit from node i
(i.e., there is a directed edge from node i
to node graph[i][j]
).
Example 1:
Input: graph = [[1,2],[3],[3],[]]
Output: [[0,1,3],[0,2,3]]
Explanation: There are two paths: 0 -> 1 -> 3 and 0 -> 2 -> 3.
Example 2:
Input: graph = [[4,3,1],[3,2,4],[3],[4],[]]
Output: [[0,4],[0,3,4],[0,1,3,4],[0,1,2,3,4],[0,1,4]]
Constraints:
n == graph.length
2 <= n <= 15
0 <= graph[i][j] < n
graph[i][j] != i
(i.e., there will be no self-loops).graph[i]
are unique.class Solution {
private var res: MutableList<List<Int>>? = null
fun allPathsSourceTarget(graph: Array<IntArray>): List<List<Int>> {
res = ArrayList()
val temp: MutableList<Int> = ArrayList()
temp.add(0)
// perform DFS
solve(graph, temp, 0)
return res as ArrayList<List<Int>>
}
private fun solve(graph: Array<IntArray>, temp: MutableList<Int>, lastNode: Int) {
if (lastNode == graph.size - 1) {
res!!.add(ArrayList(temp))
}
for (link in graph[lastNode]) {
temp.add(link)
solve(graph, temp, link)
temp.removeAt(temp.size - 1)
}
}
}