Medium
There is an undirected graph with n
nodes, where each node is numbered between 0
and n - 1
. You are given a 2D array graph
, where graph[u]
is an array of nodes that node u
is adjacent to. More formally, for each v
in graph[u]
, there is an undirected edge between node u
and node v
. The graph has the following properties:
graph[u]
does not contain u
).graph[u]
does not contain duplicate values).v
is in graph[u]
, then u
is in graph[v]
(the graph is undirected).u
and v
such that there is no path between them.A graph is bipartite if the nodes can be partitioned into two independent sets A
and B
such that every edge in the graph connects a node in set A
and a node in set B
.
Return true
if and only if it is bipartite.
Example 1:
Input: graph = [[1,2,3],[0,2],[0,1,3],[0,2]]
Output: false
Explanation: There is no way to partition the nodes into two independent sets such that every edge connects a node in one and a node in the other.
Example 2:
Input: graph = [[1,3],[0,2],[1,3],[0,2]]
Output: true
Explanation: We can partition the nodes into two sets: {0, 2} and {1, 3}.
Constraints:
graph.length == n
1 <= n <= 100
0 <= graph[u].length < n
0 <= graph[u][i] <= n - 1
graph[u]
does not contain u
.graph[u]
are unique.graph[u]
contains v
, then graph[v]
contains u
.class Solution {
fun isBipartite(graph: Array<IntArray>): Boolean {
val n = graph.size
val color = IntArray(n)
for (i in 0 until n) {
if (color[i] == 0 && !helper(graph, i, -1, color)) {
return false
}
}
return true
}
private fun helper(graph: Array<IntArray>, curr: Int, c: Int, color: IntArray): Boolean {
if (color[curr] == c) {
return true
}
color[curr] = c
for (x in graph[curr]) {
if (color[x] == c || !helper(graph, x, c * -1, color)) {
return false
}
}
return true
}
}