LeetCode in Kotlin

785. Is Graph Bipartite?

Medium

There is an undirected graph with n nodes, where each node is numbered between 0 and n - 1. You are given a 2D array graph, where graph[u] is an array of nodes that node u is adjacent to. More formally, for each v in graph[u], there is an undirected edge between node u and node v. The graph has the following properties:

A graph is bipartite if the nodes can be partitioned into two independent sets A and B such that every edge in the graph connects a node in set A and a node in set B.

Return true if and only if it is bipartite.

Example 1:

Input: graph = [[1,2,3],[0,2],[0,1,3],[0,2]]

Output: false

Explanation: There is no way to partition the nodes into two independent sets such that every edge connects a node in one and a node in the other.

Example 2:

Input: graph = [[1,3],[0,2],[1,3],[0,2]]

Output: true

Explanation: We can partition the nodes into two sets: {0, 2} and {1, 3}.

Constraints:

Solution

class Solution {
    fun isBipartite(graph: Array<IntArray>): Boolean {
        val n = graph.size
        val color = IntArray(n)
        for (i in 0 until n) {
            if (color[i] == 0 && !helper(graph, i, -1, color)) {
                return false
            }
        }
        return true
    }

    private fun helper(graph: Array<IntArray>, curr: Int, c: Int, color: IntArray): Boolean {
        if (color[curr] == c) {
            return true
        }
        color[curr] = c
        for (x in graph[curr]) {
            if (color[x] == c || !helper(graph, x, c * -1, color)) {
                return false
            }
        }
        return true
    }
}