Medium
There is an undirected graph with n nodes, where each node is numbered between 0 and n - 1. You are given a 2D array graph, where graph[u] is an array of nodes that node u is adjacent to. More formally, for each v in graph[u], there is an undirected edge between node u and node v. The graph has the following properties:
graph[u] does not contain u).graph[u] does not contain duplicate values).v is in graph[u], then u is in graph[v] (the graph is undirected).u and v such that there is no path between them.A graph is bipartite if the nodes can be partitioned into two independent sets A and B such that every edge in the graph connects a node in set A and a node in set B.
Return true if and only if it is bipartite.
Example 1:

Input: graph = [[1,2,3],[0,2],[0,1,3],[0,2]]
Output: false
Explanation: There is no way to partition the nodes into two independent sets such that every edge connects a node in one and a node in the other.
Example 2:

Input: graph = [[1,3],[0,2],[1,3],[0,2]]
Output: true
Explanation: We can partition the nodes into two sets: {0, 2} and {1, 3}.
Constraints:
graph.length == n1 <= n <= 1000 <= graph[u].length < n0 <= graph[u][i] <= n - 1graph[u] does not contain u.graph[u] are unique.graph[u] contains v, then graph[v] contains u.class Solution {
fun isBipartite(graph: Array<IntArray>): Boolean {
val n = graph.size
val color = IntArray(n)
for (i in 0 until n) {
if (color[i] == 0 && !helper(graph, i, -1, color)) {
return false
}
}
return true
}
private fun helper(graph: Array<IntArray>, curr: Int, c: Int, color: IntArray): Boolean {
if (color[curr] == c) {
return true
}
color[curr] = c
for (x in graph[curr]) {
if (color[x] == c || !helper(graph, x, c * -1, color)) {
return false
}
}
return true
}
}