LeetCode in Kotlin

710. Random Pick with Blacklist

Hard

You are given an integer n and an array of unique integers blacklist. Design an algorithm to pick a random integer in the range [0, n - 1] that is not in blacklist. Any integer that is in the mentioned range and not in blacklist should be equally likely to be returned.

Optimize your algorithm such that it minimizes the number of calls to the built-in random function of your language.

Implement the Solution class:

Example 1:

Input

[“Solution”, “pick”, “pick”, “pick”, “pick”, “pick”, “pick”, “pick”]

[[7, [2, 3, 5]], [], [], [], [], [], [], []]

Output: [null, 0, 4, 1, 6, 1, 0, 4]

Explanation:

Solution solution = new Solution(7, [2, 3, 5]);
solution.pick(); // return 0, any integer from [0,1,4,6] should be ok. Note that for every call of pick,
                 // 0, 1, 4, and 6 must be equally likely to be returned (i.e., with probability 1/4).
solution.pick(); // return 4
solution.pick(); // return 1
solution.pick(); // return 6
solution.pick(); // return 1
solution.pick(); // return 0
solution.pick(); // return 4 

Constraints:

Solution

import kotlin.random.Random

class Solution(n: Int, blacklist: IntArray) {
    private val map: MutableMap<Int, Int>
    private val upperLimit: Int

    init {
        map = HashMap()
        upperLimit = n - blacklist.size
        for (`val` in blacklist) {
            map[`val`] = -1
        }
        var j = n - 1
        for (`val` in blacklist) {
            if (`val` < upperLimit) {
                while (map.containsKey(j)) {
                    j--
                }
                map[`val`] = j
                j--
            }
        }
    }

    fun pick(): Int {
        val `val`: Int = Random.nextInt(upperLimit)
        return if (map.containsKey(`val`)) {
            map[`val`]!!
        } else `val`
    }
}

/*
 * Your Solution object will be instantiated and called as such:
 * var obj = Solution(n, blacklist)
 * var param_1 = obj.pick()
 */