Easy
Design a HashSet without using any built-in hash table libraries.
Implement MyHashSet class:
void add(key) Inserts the value key into the HashSet.bool contains(key) Returns whether the value key exists in the HashSet or not.void remove(key) Removes the value key in the HashSet. If key does not exist in the HashSet, do nothing.Example 1:
Input
["MyHashSet", "add", "add", "contains", "contains", "add", "contains", "remove", "contains"]
[[], [1], [2], [1], [3], [2], [2], [2], [2]]
Output: [null, null, null, true, false, null, true, null, false]
Explanation:
MyHashSet myHashSet = new MyHashSet();
myHashSet.add(1); // set = [1]
myHashSet.add(2); // set = [1, 2]
myHashSet.contains(1); // return True
myHashSet.contains(3); // return False, (not found)
myHashSet.add(2); // set = [1, 2]
myHashSet.contains(2); // return True
myHashSet.remove(2); // set = [1]
myHashSet.contains(2); // return False, (already removed)
Constraints:
0 <= key <= 106104 calls will be made to add, remove, and contains.class MyHashSet {
private val arr: BooleanArray = BooleanArray(1000001)
fun add(key: Int) {
arr[key] = true
}
fun remove(key: Int) {
arr[key] = false
}
operator fun contains(key: Int): Boolean {
return arr[key]
}
}
/*
* Your MyHashSet object will be instantiated and called as such:
* var obj = MyHashSet()
* obj.add(key)
* obj.remove(key)
* var param_3 = obj.contains(key)
*/