LeetCode in Kotlin

690. Employee Importance

Medium

You have a data structure of employee information, including the employee’s unique ID, importance value, and direct subordinates’ IDs.

You are given an array of employees employees where:

• employees[i].id is the ID of the ith employee.
• employees[i].importance is the importance value of the ith employee.
• employees[i].subordinates is a list of the IDs of the direct subordinates of the ith employee.

Given an integer id that represents an employee’s ID, return the total importance value of this employee and all their direct and indirect subordinates.

Example 1:

Input: employees = [[1,5,[2,3]],[2,3,[]],[3,3,[]]], id = 1

Output: 11

Explanation: Employee 1 has an importance value of 5 and has two direct subordinates: employee 2 and employee 3. They both have an importance value of 3. Thus, the total importance value of employee 1 is 5 + 3 + 3 = 11.

Example 2:

Input: employees = [[1,2,[5]],[5,-3,[]]], id = 5

Output: -3

Explanation: Employee 5 has an importance value of -3 and has no direct subordinates. Thus, the total importance value of employee 5 is -3.

Constraints:

• 1 <= employees.length <= 2000
• 1 <= employees[i].id <= 2000
• All employees[i].id are unique.
• -100 <= employees[i].importance <= 100
• One employee has at most one direct leader and may have several subordinates.
• The IDs in employees[i].subordinates are valid IDs.

Solution

import com_github_leetcode.Employee

/*
 *	// Definition for Employee.
 *	class Employee {
 *		var id:Int = 0
 *		var importance:Int = 0
 *		var subordinates:List<Int> = listOf()
 *	}
 */
class Solution {
    fun getImportance(employees: List<Employee?>, id: Int): Int {
        val map: MutableMap<Int, Employee> = HashMap()
        for (emp in employees) {
            map[emp!!.id] = emp
        }
        return calculateImportance(id, map)
    }

    private fun calculateImportance(id: Int, map: Map<Int, Employee>): Int {
        val employee = map[id]
        var sum = employee!!.importance
        for (sub in employee.subordinates) {
            sum += calculateImportance(sub, map)
        }
        return sum
    }
}

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