LeetCode in Kotlin
583. Delete Operation for Two Strings
Medium
Given two strings word1 and word2, return the minimum number of steps required to make word1 and word2 the same.
In one step, you can delete exactly one character in either string.
Example 1:
Input: word1 = “sea”, word2 = “eat”
Output: 2
Explanation: You need one step to make “sea” to “ea” and another step to make “eat” to “ea”.
Example 2:
Input: word1 = “leetcode”, word2 = “etco”
Output: 4
Constraints:
1 <= word1.length, word2.length <= 500word1andword2consist of only lowercase English letters.
Solution
class Solution {
fun minDistance(word1: String, word2: String): Int {
val m = word1.length
val n = word2.length
val dp = Array(m + 1) { IntArray(n + 1) }
for (i in 1..m) {
for (j in 1..n) {
dp[i][j] = if (word1[i - 1] == word2[j - 1]) dp[i - 1][j - 1] + 1 else Math.max(
dp[i - 1][j],
dp[i][j - 1]
)
}
}
return m + n - 2 * dp[m][n]
}
}