LeetCode in Kotlin
570. Managers with at Least 5 Direct Reports
Medium
SQL Schema
Table: Employee
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| id | int |
| name | varchar |
| department | varchar |
| managerId | int |
+-------------+---------+
id is the primary key column for this table.
Each row of this table indicates the name of an employee, their department, and the id of their manager.
If managerId is null, then the employee does not have a manager.
No employee will be the manager of themself.
Write an SQL query to report the managers with at least five direct reports.
Return the result table in any order.
The query result format is in the following example.
Example 1:
Input:
Employee table:
+-----+-------+------------+-----------+
| id | name | department | managerId |
+-----+-------+------------+-----------+
| 101 | John | A | None |
| 102 | Dan | A | 101 |
| 103 | James | A | 101 |
| 104 | Amy | A | 101 |
| 105 | Anne | A | 101 |
| 106 | Ron | B | 101 |
+-----+-------+------------+-----------+
Output:
+------+
| name |
+------+
| John |
+------+
Solution
# Write your MySQL query statement below
select e.name
from employee m left join employee e
on m.managerid = e.id
group by e.name
having count(e.name) > 4;