Medium
There are n
cities. Some of them are connected, while some are not. If city a
is connected directly with city b
, and city b
is connected directly with city c
, then city a
is connected indirectly with city c
.
A province is a group of directly or indirectly connected cities and no other cities outside of the group.
You are given an n x n
matrix isConnected
where isConnected[i][j] = 1
if the ith
city and the jth
city are directly connected, and isConnected[i][j] = 0
otherwise.
Return the total number of provinces.
Example 1:
Input: isConnected = [[1,1,0],[1,1,0],[0,0,1]]
Output: 2
Example 2:
Input: isConnected = [[1,0,0],[0,1,0],[0,0,1]]
Output: 3
Constraints:
1 <= n <= 200
n == isConnected.length
n == isConnected[i].length
isConnected[i][j]
is 1
or 0
.isConnected[i][i] == 1
isConnected[i][j] == isConnected[j][i]
class Solution {
fun findCircleNum(arr: Array<IntArray>): Int {
val parent = IntArray(arr.size)
parent.fill(-1)
var ans = 0
for (i in 0 until arr.size - 1) {
for (j in i + 1 until arr[i].size) {
if (arr[i][j] == 1) {
ans += union(i, j, parent)
}
}
}
return arr.size - ans
}
private fun union(a: Int, b: Int, arr: IntArray): Int {
val ga = find(a, arr)
val gb = find(b, arr)
if (ga != gb) {
arr[gb] = ga
return 1
}
return 0
}
private fun find(a: Int, arr: IntArray): Int {
if (arr[a] == -1) {
return a
}
arr[a] = find(arr[a], arr)
return arr[a]
}
}