Medium
Note: This is a companion problem to the System Design problem: Design TinyURL.
TinyURL is a URL shortening service where you enter a URL such as https://leetcode.com/problems/design-tinyurl
and it returns a short URL such as http://tinyurl.com/4e9iAk
. Design a class to encode a URL and decode a tiny URL.
There is no restriction on how your encode/decode algorithm should work. You just need to ensure that a URL can be encoded to a tiny URL and the tiny URL can be decoded to the original URL.
Implement the Solution
class:
Solution()
Initializes the object of the system.String encode(String longUrl)
Returns a tiny URL for the given longUrl
.String decode(String shortUrl)
Returns the original long URL for the given shortUrl
. It is guaranteed that the given shortUrl
was encoded by the same object.Example 1:
Input: url = “https://leetcode.com/problems/design-tinyurl”
Output: “https://leetcode.com/problems/design-tinyurl”
Explanation:
Solution obj = new Solution();
string tiny = obj.encode(url); // returns the encoded tiny url.
string ans = obj.decode(tiny); // returns the original url after deconding it.
Constraints:
1 <= url.length <= 104
url
is guranteed to be a valid URL.class Codec {
private val map: MutableMap<String, String> = HashMap()
private var n = 0
// Encodes a URL to a shortened URL.
fun encode(longUrl: String): String {
n++
var ans = "http://tinyurl.com/"
ans += n.toString()
map[ans] = longUrl
return ans
}
// Decodes a shortened URL to its original URL.
fun decode(shortUrl: String): String? {
return map[shortUrl]
}
}
/*
* Your Codec object will be instantiated and called as such:
* var obj = Codec()
* var url = obj.encode(longUrl)
* var ans = obj.decode(url)
*/