LeetCode in Kotlin

412. Fizz Buzz

Easy

Given an integer n, return a string array answer (1-indexed) where:

• answer[i] == "FizzBuzz" if i is divisible by 3 and 5.
• answer[i] == "Fizz" if i is divisible by 3.
• answer[i] == "Buzz" if i is divisible by 5.
• answer[i] == i (as a string) if none of the above conditions are true.

Example 1:

Input: n = 3

Output: [“1”,”2”,”Fizz”]

Example 2:

Input: n = 5

Output: [“1”,”2”,”Fizz”,”4”,”Buzz”]

Example 3:

Input: n = 15

Output: [“1”,”2”,”Fizz”,”4”,”Buzz”,”Fizz”,”7”,”8”,”Fizz”,”Buzz”,”11”,”Fizz”,”13”,”14”,”FizzBuzz”]

Constraints:

• 1 <= n <= 104

Solution

class Solution {
    fun fizzBuzz(n: Int): Array<String> = Array<String>(n) { index ->
        val value = index + 1
        when {
            (value % 3 == 0 && value % 5 == 0) -> "FizzBuzz"
            (value % 3 == 0) -> "Fizz"
            (value % 5 == 0) -> "Buzz"
            else -> "$value"
        }
    }
}

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