Medium
Given a string s
and an integer k
, return the length of the longest substring of s
such that the frequency of each character in this substring is greater than or equal to k
.
Example 1:
Input: s = “aaabb”, k = 3
Output: 3
Explanation: The longest substring is “aaa”, as ‘a’ is repeated 3 times.
Example 2:
Input: s = “ababbc”, k = 2
Output: 5
Explanation: The longest substring is “ababb”, as ‘a’ is repeated 2 times and ‘b’ is repeated 3 times.
Constraints:
1 <= s.length <= 104
s
consists of only lowercase English letters.1 <= k <= 105
class Solution {
fun longestSubstring(s: String, k: Int): Int {
return helper(s, k, 0, s.length)
}
private fun helper(s: String, k: Int, start: Int, end: Int): Int {
if (end - start < k) {
return 0
}
val nums = IntArray(26)
for (i in start until end) {
nums[s[i].code - 'a'.code]++
}
for (i in start until end) {
if (nums[s[i].code - 'a'.code] < k) {
var j = i + 1
while (j < s.length && nums[s[j].code - 'a'.code] < k) {
j++
}
return Math.max(helper(s, k, start, i), helper(s, k, j, end))
}
}
return end - start
}
}