LeetCode in Kotlin
390. Elimination Game
Medium
You have a list arr of all integers in the range [1, n] sorted in a strictly increasing order. Apply the following algorithm on arr:
- Starting from left to right, remove the first number and every other number afterward until you reach the end of the list.
- Repeat the previous step again, but this time from right to left, remove the rightmost number and every other number from the remaining numbers.
- Keep repeating the steps again, alternating left to right and right to left, until a single number remains.
Given the integer n, return the last number that remains in arr.
Example 1:
Input: n = 9
Output: 6
Explanation:
arr = [1, 2, 3, 4, 5, 6, 7, 8, 9]
arr = [2, 4, 6, 8]
arr = [2, 6]
arr = [6]
Example 2:
Input: n = 1
Output: 1
Constraints:
1 <= n <= 109
Solution
class Solution {
fun lastRemaining(n: Int): Int {
return if (n == 1) 1 else 2 * (n / 2 - lastRemaining(n / 2) + 1)
}
}