Easy
Given a string s, find the first non-repeating character in it and return its index. If it does not exist, return -1.
Example 1:
Input: s = “leetcode”
Output: 0
Example 2:
Input: s = “loveleetcode”
Output: 2
Example 3:
Input: s = “aabb”
Output: -1
Constraints:
1 <= s.length <= 105s consists of only lowercase English letters.class Solution {
    fun firstUniqChar(s: String): Int {
        var ans = Int.MAX_VALUE
        var i = 'a'
        while (i <= 'z') {
            val ind = s.indexOf(i)
            if (ind != -1 && ind == s.lastIndexOf(i)) {
                ans = Math.min(ans, ind)
            }
            i++
        }
        return if (ans == Int.MAX_VALUE) {
            -1
        } else {
            ans
        }
    }
}