Easy
Given two strings s and t, return true if t is an anagram of s, and false otherwise.
An Anagram is a word or phrase formed by rearranging the letters of a different word or phrase, typically using all the original letters exactly once.
Example 1:
Input: s = “anagram”, t = “nagaram”
Output: true
Example 2:
Input: s = “rat”, t = “car”
Output: false
Constraints:
1 <= s.length, t.length <= 5 * 104s and t consist of lowercase English letters.Follow up: What if the inputs contain Unicode characters? How would you adapt your solution to such a case?
class Solution {
fun isAnagram(s: String, t: String): Boolean {
if (s.length != t.length) {
return false
}
val counter = IntArray(26)
for (i in 0 until s.length) {
counter[s[i] - 'a']++
counter[t[i] - 'a']--
}
for (count in counter) {
if (count != 0) {
return false
}
}
return true
}
}