Medium
Given an integer array nums
, return an array answer
such that answer[i]
is equal to the product of all the elements of nums
except nums[i]
.
The product of any prefix or suffix of nums
is guaranteed to fit in a 32-bit integer.
You must write an algorithm that runs in O(n)
time and without using the division operation.
Example 1:
Input: nums = [1,2,3,4]
Output: [24,12,8,6]
Example 2:
Input: nums = [-1,1,0,-3,3]
Output: [0,0,9,0,0]
Constraints:
2 <= nums.length <= 105
-30 <= nums[i] <= 30
nums
is guaranteed to fit in a 32-bit integer.Follow up: Can you solve the problem in O(1)
extra space complexity? (The output array does not count as extra space for space complexity analysis.)
class Solution {
fun productExceptSelf(nums: IntArray): IntArray {
var product = 1
val ans = IntArray(nums.size)
for (num in nums) {
product = product * num
}
for (i in nums.indices) {
if (nums[i] != 0) {
ans[i] = product / nums[i]
} else {
var p = 1
for (j in nums.indices) {
if (j != i) {
p = p * nums[j]
}
}
ans[i] = p
}
}
return ans
}
}