Easy
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.
Implement the MinStack
class:
MinStack()
initializes the stack object.void push(int val)
pushes the element val
onto the stack.void pop()
removes the element on the top of the stack.int top()
gets the top element of the stack.int getMin()
retrieves the minimum element in the stack.Example 1:
Input
["MinStack","push","push","push","getMin","pop","top","getMin"]
[[],[-2],[0],[-3],[],[],[],[]]
Output: [null,null,null,null,-3,null,0,-2]
Explanation:
MinStack minStack = new MinStack();
minStack.push(-2);
minStack.push(0);
minStack.push(-3);
minStack.getMin(); // return -3
minStack.pop();
minStack.top(); // return 0
minStack.getMin(); // return -2
Constraints:
-231 <= val <= 231 - 1
pop
, top
and getMin
operations will always be called on non-empty stacks.3 * 104
calls will be made to push
, pop
, top
, and getMin
.class MinStack() {
private val stack: ArrayDeque<Pair<Int, Int>> = ArrayDeque()
fun push(x: Int) {
val min: Int = if (stack.isEmpty()) {
x
} else {
getMin()
}
stack.addLast(x to minOf(min, x))
}
fun pop() {
stack.removeLast()
}
fun top(): Int {
return stack
.last()
.first
}
fun getMin(): Int {
return stack
.last()
.second
}
}
/*
* Your MinStack object will be instantiated and called as such:
* var obj = MinStack()
* obj.push(`val`)
* obj.pop()
* var param_3 = obj.top()
* var param_4 = obj.getMin()
*/