LeetCode in Kotlin
53. Maximum Subarray
Medium
Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.
A subarray is a contiguous part of an array.
Example 1:
Input: nums = [-2,1,-3,4,-1,2,1,-5,4]
Output: 6
Explanation: [4,-1,2,1] has the largest sum = 6.
Example 2:
Input: nums = [1]
Output: 1
Example 3:
Input: nums = [5,4,-1,7,8]
Output: 23
Constraints:
1 <= nums.length <= 105-104 <= nums[i] <= 104
Follow up: If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.
Solution
class Solution {
fun maxSubArray(nums: IntArray): Int {
var nextMax = nums[0]
var curMax = nums[0]
for (i in 1 until nums.size) {
nextMax += nums[i]
if (nextMax < nums[i]) {
nextMax = nums[i]
}
if (nextMax > curMax) {
curMax = nextMax
}
}
return curMax
}
}