LeetCode in Kotlin
32. Longest Valid Parentheses
Hard
Given a string containing just the characters '(' and ')', find the length of the longest valid (well-formed) parentheses substring.
Example 1:
Input: s = “(()”
Output: 2
Explanation: The longest valid parentheses substring is “()”.
Example 2:
Input: s = “)()())”
Output: 4
Explanation: The longest valid parentheses substring is “()()”.
Example 3:
Input: s = “”
Output: 0
Constraints:
0 <= s.length <= 3 * 104s[i]is'(', or')'.
Solution
class Solution {
fun longestValidParentheses(s: String): Int {
var max = 0
var left = 0
var right = 0
val n = s.length
var ch: Char
for (i in 0 until n) {
ch = s[i]
if (ch == '(') {
left++
} else {
right++
}
if (right > left) {
left = 0
right = 0
}
if (left == right) {
max = Math.max(max, left + right)
}
}
left = 0
right = 0
for (i in n - 1 downTo 0) {
ch = s[i]
if (ch == '(') {
left++
} else {
right++
}
if (left > right) {
left = 0
right = 0
}
if (left == right) {
max = Math.max(max, left + right)
}
}
return max
}
}